2525

Author: rimgosu

leetcode3/변지협/v3/2525. Categorize Box According to Criteria.py

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+
+'''
+1. 아이디어 :
+문제에 나온 조건에 맞게 분류한다.
+
+2. 시간복잡도 :
+o(1)
+
+3. 자료구조/알고리즘 :
+'''
+
+class Solution:
+    def categorizeBox(self, length: int, width: int, height: int, mass: int) -> str:
+        volume = length * width * height
+        
+        heavy = True if mass >= 100 else False
+        bulky = False
+        
+        if length >= 10 ** 4 or width >= 10 ** 4 or height >= 10 ** 4 or volume >= 10 ** 9:
+            bulky = True
+        
+        if heavy and bulky:
+            return 'Both'
+        elif not heavy and not bulky:
+            return "Neither"
+        elif bulky and not heavy:
+            return "Bulky"
+        else:
+            return "Heavy"