Updating Lazy Delete method in Employee Code

[SharafEldein]

Problem :

ArabicCompetitiveProgramming/18-Programming-4kids/11_homework_10_answer_employees_v1.cpp

Here is my code without Lazy Delete Method:

#include
#include
#include
using namespace std;

const int MAX = 50;

int salary[MAX];
int age[MAX];
char gendrL[MAX];
string name[MAX];
int added = 0;

int main() {
while (true)
{
int choice = -1;
cout << "\n1) Add Employee Data \n";
cout << "2) Print All Employees \n";
cout << "3) Remove employee by age \n";
cout << "4) Update Employee salary \n\n";

	cin >> choice;
	
	while (choice < 1 || 4 < choice)
	{
		cout << "Invalid Choice. \n";
		cin >> choice;
	}

	switch (choice)
	{
	case 1:
		cout << "Enter  Name, Age, Salary, and Gender Letter(M/F) :   ";
		cin >> name[added] >> age[added] >> salary[added] >> gendrL[added];
		added++;
		break;
	case 2:
		cout << setw(10) << "NAME" << setw(12) << "Salary" << setw(10) << "Age" << setw(10) << "Gender" << "\n";
		for (int i = 0; i < 45; i++)
			cout << '-';
		cout << endl;

		for (int i = 0; i < added; i++) {
			cout << i + 1 << setw(10) << name[i] << setw(10) << salary[i] << setw(10) << age[i] << setw(10) << gendrL[i] << "\n";
		}
		break;
	case 3:
		int start, end;
		cout << "Enter Starting and Ending age:  ";
		cin >> start >> end;
		for (int i = 0; i < added; i++)
		{
			if (age[i] <= end && age[i] >= start) {
				for (int j = i; j < added; j++)
				{
					age[j] = age[j + 1];
					name[j] = name[j + 1];
					salary[j] = salary[j + 1];
					gendrL[j] = gendrL[j + 1];
				}
				added--;
				i--;
			}
		}
		break;
	
	case 4:
		string updateName;
		int updateSalary;
		int oldSalary = 0;
		cout << "Enter Employee Name, and Updated Salary:	";
		cin >> updateName >> updateSalary;

		for (int i = 0; i < added; i++)
			if (name[i] == updateName){
				oldSalary = salary[i];
				salary[i] = updateSalary;
			}
		break;
	}
}

}