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Mutable references vs self-referential structs #148

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@RalfJung

Turns out that stacked borrows and self-referential generators don't go well together. This code fails in Miri:

#![feature(generators, generator_trait)]

use std::{
    ops::{Generator, GeneratorState},
    pin::Pin,
};

fn firstn() -> impl Generator<Yield = u64, Return = ()> {
    static move || {
        let mut num = 0;
        let num = &mut num;

        yield *num;
        *num += 1; //~ ERROR: borrow stack

        yield *num;
        *num += 1;

        yield *num;
        *num += 1;
    }
}

fn main() {
    let mut generator_iterator = firstn();
    let mut pin = unsafe { Pin::new_unchecked(&mut generator_iterator) };
    let mut sum = 0;
    while let GeneratorState::Yielded(x) = pin.as_mut().resume() {
        sum += x;
    }
    println!("{}", sum);
}

The reason it fails is that each time through the loop, we call Pin::as_mut, which creates a fresh mutable reference to the generator. Since mutable references are unique, that invalidates the pointer that points from one field of the generator to another.

This is basically a particularly bad instance of #133.

Cc @cramertj @tmandry @nikomatsakis @arielb1

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  1. added
    A-aliasing-modelTopic: Related to the aliasing model (e.g. Stacked/Tree Borrows)
    on Jun 21, 2019
  2. RalfJung commented on Jun 23, 2019

    @RalfJung
    MemberAuthor

    In some sense there are two problems here:

    • When a Pin<&mut T> gets passed around, it gets retagged the same way as an &mut T, assuring uniqueness of this pointer to the entire memory range. This is probably not something we want. So maybe we need a "no retagging for private fields" kind of thing, similar to what we might need for protectors. This is the (relatively) easy part.
    • However, even just calling Pin::as_mut creates a mutable reference internally (before wrapping it in Pin again). So even if we fix the above, we'd still assert uniqueness here. In some sense it would be more correct if a Pin<&mut T> would actually be represented as a NonNull<T>, as that's a more honest reflection of the aliasing situation: it's not a unique pointer, there can be pointers inside this data structure that alias. This is the hard part.

    If we still had PinMut as a separate type, this would be fixable, but with Pin<impl Deref>, that's hard. And even then, map_unchecked_mut still creates a mutable reference and even passes it as a function argument, which is about as strongly asserting uniqueness as we can -- and which we don't want, aliasing pointers are allowed to exist.

  3. RalfJung commented on Jun 25, 2019

    @RalfJung
    MemberAuthor

    If we ignore the fact that references are wrapped inside the Pin struct, self-referential generators do the equivalent of:

    fn main() {
        let mut local = 42;
        let raw_ptr = &mut local as *mut i32; // create raw pointer
        let safe_ref = &mut local; // create a reference, which is unique, and hence invalidates the raw pointer
        println!("{}", unsafe { *raw_ptr }); // UB
    }

    I explicitly wanted that code to be UB. While raw pointers aliasing with each other is allowed, having a single raw pointer and a mutable reference acts pretty much like having two mutable references -- after all, between the two of them, it's enough if one side does not allow aliasing, since "aliases-with" is a symmetric relation. If we replace raw_ptr by another reference above, the code is rejected by both the borrow checker and Stacked Borrows.

    So to fix this problem, I see two general options:

    1. "Hide" references in struct fields from Stacked Borrows. Then the implementation of Pin methods would have to do lots of transmute to avoid ever creating a "bare" reference. And map_unchecked_mut has a problem. It should probably use raw pointers (and RFC for an operator to take a raw reference rfcs#2582 to get a field address). On the other hand, at least we have a plan.
    2. Allow the example code above. We would have to somehow "lazily" activate mutable references. It's a bit like two-phase borrows but worse. I don't have a very concrete idea what this would look like, but I think Stacked Borrows would have to become Tree-shaped Borrows or so -- a stack just does not have enough structure.
  4. HadrienG2 commented on Jun 29, 2019

    @HadrienG2

    @RalfJung: Could this be resolved by turning Pin<&'a mut T> into some abstraction around (&'a UnsafeCell<T>; PhantomData<&'a mut T>) that does not actually hold a reference, but only behaves like one and spawns actual references on demand?

    This would likely require turning Pin into Compiler Magic(tm) that is hard to implement for user-defined pointer types, though, and I can imagine backwards-incompatible implications in other areas such as changing the safety contract for extracting mutable references from Pin...

    EDIT: Ah, I see that you explored a NonNull-based variant of this strategy above.

  5. RalfJung commented on Jun 29, 2019

    @RalfJung
    MemberAuthor

    You don't need UnsafeCell, *mut T would do it. And yes that's basically what I had in mind with option (1).

  6. CAD97 commented on Jun 29, 2019

    @CAD97
    Contributor

    The way I understand how Pin works, the self referential references borrow their validity from the one in the pin. So under SB, they're retagged from the pin.

    The most minimal change that would make pin play nicely with SB I think would be to somehow keep the interior references valid even while the unsafe map_unchecked_mut reference is used.

    Could it be possible to not retag for pin's map_unchecked_mut and only pop tags when the reference is used to access that memory location? (This is super spitball, sorry)

  7. RalfJung commented on Jun 29, 2019

    @RalfJung
    MemberAuthor

    The way I understand how Pin works, the self referential references borrow their validity from the one in the pin. So under SB, they're retagged from the pin.

    Correct.

    However, then the pin itself eventually gets retagged, and that kills the self-referential borrows. This currently happens all the time, but could be reduced to just "inside the Pin implementation" if we make retag respect privacy, or just generally not enter structs, or so.

    Could it be possible to not retag for pin's map_unchecked_mut

    Well it'd need a magic marker or so.

    and only pop tags when the reference is used to access that memory location? (This is super spitball, sorry)

    That's basically option (2) from above.

  8. changed the title [-]Stacked Borrows vs self-referential generators[/-] [+]Stacked Borrows vs self-referential structs[/+] on Aug 13, 2019
  9. RalfJung commented on Aug 13, 2019

    @RalfJung
    MemberAuthor

    #194 indicates that this is a problem with self-referential structs in general, not just self-referential generators. That's not surprising, so I generalized the issue title.

  10. Aaron1011 commented on Aug 22, 2019

    @Aaron1011

    @RalfJung: Related to your example of:

    fn main() {
        let mut local = 42;
        let raw_ptr = &mut local as *mut i32; // create raw pointer
        let safe_ref = &mut local; // create a reference, which is unique, and hence invalidates the raw pointer
        println!("{}", unsafe { *raw_ptr }); // UB
    }
    

    While working on pin-project, I wanted to write this code:

    use std::pin::Pin;
    
    struct Foo {
        // #[pin]
        field1: u8,
        field2: bool
    }
    
    struct FooProj<'a> {
        __self_ptr: *mut Foo,
        field1: Pin<&'a mut u8>,
        field2: &'a mut bool
    }
    
    impl Foo {
        fn project<'a>(self: Pin<&'a mut Self>) -> FooProj<'a> {
            let this = unsafe { self.get_unchecked_mut() };
            let __self_ptr: *mut Foo = this;
            let field1  = unsafe { Pin::new_unchecked(&mut this.field1) };
            let field2 = &mut this.field2;
            FooProj {
                __self_ptr,
                field1,
                field2
            }
        }
    }
    
    impl<'a> FooProj<'a> {
        fn unproject(self) -> Pin<&'a mut Foo> {
            unsafe {
                let this: &mut Foo = &mut *self.__self_ptr;
                Pin::new_unchecked(this)
            }
        }
    }
    
    fn main() {
        let mut foo = Foo { field1: 25, field2: true };
        let foo_pin: Pin<&mut Foo> = Pin::new(&mut foo);
        let foo_proj: FooProj = foo_pin.project();
        let foo_orig: Pin<&mut Foo> = foo_proj.unproject();
    }

    The key thing here is the unproject method. Basically, I want to be able to the following:

    1. Convert an &mut Self to a *mut Self
    2. Create mutable references to fields of Self (&mut self.field, etc.)
    3. Later, upgrade the *mut Self to a &mut Self, after all of the mutable fields references have gone out of scope.

    However, Miri flags this as UB for (I believe) a similar reason as your example - creating a mutable reference to a field ends up transitively asserts that we have unique ownership of the base type. Therefore, any pre-existing raw pointers to the base type will be invalidated.

    Allowing this kind of pattern would make pin-project much more useful. It would allow the following pattern:

    impl MyType {
    	fn process(self: Pin<&mut Self>) {
            let this = self.project();
    
            // Use a pin-projected field - e.g. poll a wrapped future
            ...
    
    
            // Construct a new instance of MyType - e.g. a new enum variant
            let new_foo: MyType = ...;
            // Overwrite ourself using Pin::set
            let new_self: Pin<&mut Self> = this.unproject();
            new_self.set(new_foo);
        } 
    

    This is especially useful when working with enums - here's a real-world example in Hyper.

    However, I can't see a way to avoid creating and later 'upgrading' a raw pointer when trying to safely abstract this pattern in pin-project.

  11. CAD97 commented on Aug 22, 2019

    @CAD97
    Contributor

    With arbitrary_self_types, pin-project could take self: &mut Pin<&mut Self> to get a lifetime to tie the projection to, and let NLL take care of the projection lifetime then allow using self again. example.

    It is the same kind of reasoning as to why this could be sound: in the self-referential case, it's the whole pointer existing that invalidates the part pointers, though their usage regions are disjoint. In the unproject case, it's the part pointers invalidating the whole pointer, even though they are statically required to be used in disjoint regions.

  12. added a commit that references this issue on Aug 23, 2019
  13. 17 remaining items

  14. RalfJung commented on Jan 2, 2022

    @RalfJung
    MemberAuthor

    One particular concern I have is regarding what happens when you have an Unpin field of a !Unpin type.

    The moment you create a reference to that field, it would require uniqueness.

  15. RalfJung commented on Jan 2, 2022

    @RalfJung
    MemberAuthor

    have a version of miri that disables uniqueness for !Unpin types

    As in, make this configurable via a flag? That's possible, but then the question remains what the default should be.

  16. Darksonn commented on Jan 2, 2022

    @Darksonn
    Member

    Whether it's a flag or not is not that important to me.

    The moment you create a reference to that field, it would require uniqueness.

    Yes, that was the impression I got as well. In Tokio I have been doing this because it's unclear to me exactly what is required:

    https://github.com/tokio-rs/tokio/blob/12dd06336d2af8c2d735d4d9e3dc0454ad7942a0/tokio/src/util/linked_list.rs#L285-L334

    However, we haven't been doing the same for all structs containing a Pointers. Tokio's MSRV is too old for the addr_of! macro, so it's pretty difficult to do it everywhere. It's also difficult if types are not Copy.

  17. RalfJung commented on Jan 2, 2022

    @RalfJung
    MemberAuthor

    Hm, I don't quite understand what that Pointers struct is about, but indeed without addr_of! some code cannot be written properly. Would it be an option to have a build.rs set a cfg flag such that on recent enough Rust, addr_of! is used, but older Rust fall back to &expr as *const _? (Somewhat like the maybe-uninit crate.)

    But anyway that seems unrelated to self-referential generators, so we should probably move the discussion elsewhere (e.g. Zulip).

  18. added a commit that references this issue on Jan 9, 2022
  19. mitsuhiko commented on Feb 18, 2022

    @mitsuhiko

    I believe I'm running into a variation of this here: mitsuhiko/deser#37 — While I don't have a generator, I have the situation where I am trying to stash away a value temporarily on an iterator like type for one iteration and the returning the value invalidates all pointers.

    While what I'm doing is probably not a very common issue, it seems like you can run into this in the absence of generators, futures and pin as well.

  20. thomcc commented on Feb 18, 2022

    @thomcc
    Member

    Yes, it's definitely a thing that happens outside of the case that's mentioned at the start.

  21. RalfJung commented on Feb 18, 2022

    @RalfJung
    MemberAuthor

    This issue here is specific about self-referential data structures though, not sure how those would come up in an iterator? So on first sight that does not really sound like the same problem.

  22. mitsuhiko commented on Feb 18, 2022

    @mitsuhiko

    @RalfJung it's not a traditional iterator, it's a struct that is iterated like this:

    while let Some(value) = thing.next()? { ... }

    And it works by stashing data onto self for next() to return a borrow to. Since I create self referential data within the "iterator" to make data survive until the next iteration in the form of some state machine, I am getting some pointers invalidated presumably because fn next has &mut self. That's at least my interpretation of what is happening.

  23. CAD97 commented on May 9, 2022

    @CAD97
    Contributor

    Cross-linking recent zulip discussion about "UnsafeMutCell": https://rust-lang.zulipchat.com/#narrow/stream/213817-t-lang/topic/aliased.20mutability

  24. added
    S-pending-designStatus: Resolving this issue requires addressing some open design questions
    on Aug 1, 2023
  25. changed the title [-]Stacked Borrows vs self-referential structs[/-] [+]Mutable references vs self-referential structs[/+] on Aug 1, 2023
  26. JakobDegen commented on Aug 1, 2023

    @JakobDegen
    Contributor

    Visiting for backlog bonanza. Retitling to clarify that this is not SB specific

  27. RalfJung commented on Aug 1, 2023

    @RalfJung
    MemberAuthor
  28. WarpspeedSCP commented on Aug 19, 2023

    @WarpspeedSCP

    As an observer, a thought occurred regarding the UnsafeWindow proposal. Would it be possible to prevent this type from ever being referenced? As in, it should be treated effectively like an UnsafeCell, but creating direct references to an UnsafeWindow should be disallowed.

    Based on a minute's worth of thought it seems like if UnsafeWindow were allowed to be turned into a reference, we run into the same set of problems every other proposal has, where we end up having to make exemptions for certain referencing patterns wholesale where we could instead restrict it to certain regions through api enforcement.

    It feels like an approach where UnsafeWindow would instead somehow provide non aliasing mutable references to the inner value may allow for easier restrictions on what is allowed in general while still allowing the self referential behaviour.

    Thinking in terms of mutability, Id say UnsafeWindow would behave like UnsafeCell, as in an immutable UnsafeWindow would still allow for multiple mutable references to the inner value to exist.

    In summary, UnsafeWindow would be ownership only, and dereferencing an unsafe window should result in, say, a new reference that is implicitly assumed to be non aliasing. Usage in ways that allow the reference to exist outside of the variable's scope would be UB, but I can' figure out if there is a way to statically disallow such a situation, aince if we attach ifetimes to the created references it would imply they are tied to the UnsafeWindow and we may end up looping around to the aliasing mutable reference problem again.

    Welp, that RFC sort of is exactly what I envisioned.

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